Wireshark-users: Re: [Wireshark-users] Pcap files
From: Rayne <hjazz6@xxxxxxxxx>
Date: Thu, 22 Oct 2009 19:57:28 -0700 (PDT)
I'm actually looking to create a new packet and then send it out through an NIC for further processing. That was why I'm questioning what contents the packet should contain, other than the L2-L7 data. I now understand that the newly created packet should only contain the L2-L7 data, and not include the 16-byte per-packet record header. It looks like all I need to do is allocate a block of memory to hold the L2-L7 packet content. Thank you. Regards, Rayne --- On Thu, 10/22/09, Guy Harris <guy@xxxxxxxxxxxx> wrote: > From: Guy Harris <guy@xxxxxxxxxxxx> > Subject: Re: [Wireshark-users] Pcap files > To: "Community support list for Wireshark" <wireshark-users@xxxxxxxxxxxxx> > Date: Thursday, October 22, 2009, 1:16 AM > > On Oct 21, 2009, at 5:57 PM, Rayne wrote: > > > So am I right to say that if I were to capture a > packet, that packet > > should only consist of the 16-byte packet header and > the L2-L7 > > content. > > If you were to capture a packet, that packet would consist > of whatever > data the packet capture mechanism supplied to you, > including any > pseudo-headers such as a header giving radio information > for 802.11 > packets. For example, if it's an 802.11 packet, the > "packet header" > would include the variable-length 802.11 header, and would > have a > radio header before it if that happened to be what the > driver and > capture mechanism supplied, and if it's an Ethernet packet, > it would > consist of the *12*-byte packet header, possibly followed > by an 802.2 > header, possibly followed by a SNAP header if there's an > 802.2 header, > followed by the payload. > > > But if I were to write that packet to a file of the > libpcap format, > > then the 24-byte "header" will be prepended to the > file? > > If you were to write one or more packets to a pcap file, > the first 24 > bytes of the file will be the pcap file header, followed by > the > records for the packets; each record would consist of a > 16-byte per- > packet header, followed by the packet data. > > The 16-byte record header is *NOT* part of the > packet. If you were to > capture a packet with libpcap/WinPcap, using > pcap_dispatch() or > pcap_loop(), a pointer to the 16-byte per-packet header for > the packet > will be supplied to you as a separate item from the pointer > to the raw > packet data; you will not get passed a pointer to a single > chunk of > data starting with the 16-byte per-packet header with the > packet data > immediately following it. > > That's also true if you were to read an existing capture > file with > libpcap/WinPcap, using pcap_dispatch() or pcap_loop(). > > What is it you are trying to do here? > > Read a pcap-format file? If so, you should probably > consider using > libpcap/WinPcap to read the file. > > Write a pcap-format file? If so, you should probably > still consider > using libpcap/WinPcap (pcap_dump_open(), pcap_dump(), > > pcap_dump_close()). > ___________________________________________________________________________ > Sent via: Wireshark-users mailing list <wireshark-users@xxxxxxxxxxxxx> > Archives: http://www.wireshark.org/lists/wireshark-users > Unsubscribe: https://wireshark.org/mailman/options/wireshark-users > > mailto:wireshark-users-request@xxxxxxxxxxxxx?subject=unsubscribe >
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- Re: [Wireshark-users] Pcap files
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