(1) There is no error message other than it fails immediately when beginning building "qtui" (at about 70% of the way into make for wireshark-3.4.4)
You should have an error message, please check above in the build log.
I just built Wireshark 3.4.4 (taken from the git tag, not the source tarball in case it matters) without any issue with an out of tree build (folder named build.wireshark) both with make and ninja, using CMake 3.16.3, Qt 5.12.8 and gcc/g++ 9.3.0 on Ubuntu 20.04.2.
(2) Good point. Wireshark uses dissectors to provide details of packets, as you point out. So then the dissector source code provides the details of the dissector.
On Apr 15, 2021, at 12:55 AM, Vincent Randal <vtrandal@xxxxxxxxx> wrote:
> (1) building Wireshark in build.wireshark fails
> The solution here is to use "build" as the name of the build directory and then make succeeds. Otherwise, if the build directory has some other name like build.wireshark then make fails at about 70% when building qtui.
What's the error that it reports? I can't reproduce that on my Mac with the current tip of the main branch.
> (2) how to get dissector details without packet
> I see there is "Decode as ..." in the Analzye menu of Wireshark. That looks very useful. I think I can use that to get Wireshark to ... uh well ... decode an already decoded packet as something else.
>
> But what about something that shows me what Wireshark thinks about a dissector even without a packet? Is that possible? Can Wireshark show me the details of a dissector without a packet to dissect?
That depends on what you mean by "the details of the dissector". Normally, what Wireshark shows is the details of a *packet*, which, obviously, requires a packet; what would the details of a *dissector* be?
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