[季红 <jihong_seu@xxxxxxx>]

Dear sir :

        Please excuse me for  I'm taking the liberty of writing to you.   I' m a chinese. I have a wireshark dissector question which I would like to ask you.  To make my example as plain

 and interesting as possible,  so I use the example of the official website :https://www.wireshark.org/docs/wsdg_html_chunked/ChDissectAdd.html .  

Example 9.12. Enhancing the display.

static void
dissect_foo(tvbuff_t *tvb, packet_info *pinfo, proto_tree *tree)
{
    guint8 packet_type = tvb_get_guint8(tvb, 0);

    col_set_str(pinfo->cinfo, COL_PROTOCOL, "FOO");
    /* Clear out stuff in the info column */
    col_clear(pinfo->cinfo,COL_INFO);
    col_add_fstr(pinfo->cinfo, COL_INFO, "Type %s",
             val_to_str(packet_type, packettypenames, "Unknown (0x%02x)"));

    if (tree) { /* we are being asked for details */
        proto_item *ti = NULL;
        proto_tree *foo_tree = NULL;
        gint offset = 0;

        ti = proto_tree_add_item(tree, proto_foo, tvb, 0, -1, ENC_NA);
        proto_item_append_text(ti, ", Type %s",
            val_to_str(packet_type, packettypenames, "Unknown (0x%02x)"));
        foo_tree = proto_item_add_subtree(ti, ett_foo);
        proto_tree_add_item(foo_tree, hf_foo_pdu_type, tvb, offset, 1, ENC_BIG_ENDIAN);
        offset += 1;
    }
}

1.Suppose there are three packets, then dissect_foo is called many times?  

2. If I click one row in wireshark 's user interface， then dissect_foo  will be called many times?

3. How can I debug the code slice:

    if (tree) { /* we are being asked for details */
        proto_item *ti = NULL;
        proto_tree *foo_tree = NULL;
        gint offset = 0;

        ti = proto_tree_add_item(tree, proto_foo, tvb, 0, -1, ENC_NA);
        proto_item_append_text(ti, ", Type %s",
            val_to_str(packet_type, packettypenames, "Unknown (0x%02x)"));
        foo_tree = proto_item_add_subtree(ti, ett_foo);
        proto_tree_add_item(foo_tree, hf_foo_pdu_type, tvb, offset, 1, ENC_BIG_ENDIAN);
        offset += 1;
    }

Thanks ! Looking forward to your reply.