How can a frame size of 2774 be captured on a 100M
full duplex Ethernet link?
Thanks
No. Time Source Destination
Protocol Info
520 64.873442 205.248.160.254 172.29.110.2
FTP-DATA FTP Data: 2720 bytes
Frame 520 (2774 bytes on wire, 2774 bytes captured)
Arrival Time: Sep 22, 2004 07:19:27.609254000
Time delta from previous packet: 0.000220000
seconds
Time since reference or first frame: 64.873442000
seconds
Frame Number: 520
Packet Length: 2774 bytes
Capture Length: 2774 bytes
Ethernet II, Src: 00:30:f1:41:82:4d, Dst:
00:60:d1:14:09:bd
Destination: 00:60:d1:14:09:bd (205.248.160.1)
Source: 00:30:f1:41:82:4d (205.248.160.254)
Type: IP (0x0800)
Internet Protocol, Src Addr: 205.248.160.254
(205.248.160.254), Dst Addr: 172.29.110.2
(172.29.110.2)
Version: 4
Header length: 20 bytes
Differentiated Services Field: 0x00 (DSCP 0x00:
Default; ECN: 0x00)
Total Length: 2760
Identification: 0x19ea (6634)
Flags: 0x04 (Don't Fragment)
Fragment offset: 0
Time to live: 128
Protocol: TCP (0x06)
Header checksum: 0x0000 (incorrect, should be
0x4d2f)
Source: 205.248.160.254 (205.248.160.254)
Destination: 172.29.110.2 (172.29.110.2)
Transmission Control Protocol, Src Port: ftp-data
(20), Dst Port: 1124 (1124), Seq: 1, Ack: 1, Len: 2720
Source port: ftp-data (20)
Destination port: 1124 (1124)
Sequence number: 1 (relative sequence number)
Next sequence number: 2721 (relative sequence
number)
Acknowledgement number: 1 (relative ack number)
Header length: 20 bytes
Flags: 0x0010 (ACK)
Window size: 17680
Checksum: 0x891d (incorrect, should be 0x83cc)
FTP Data
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